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20 November, 11:28

A sample of diborane gas has a pressure of 345 torr at a temperature of - 15c and volume of 3.48L if conditions are changed so that the temperature is 36c and the pressure is 468 torr what will be the volume of the sample

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  1. 20 November, 11:49
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    Answer: 3.05L = V2

    Explanation:

    using

    P1V1/T1=P2V2/T2

    where p1 = 345torr

    T1, tempertaure = - 15c + 273=258K

    T2, temperature = 36 + 273=309K

    p2, Pressure = 468 torr

    V2=?

    P1V1/T1=P2V2/T2

    v2=P1V1T2/T1P2 = 345X3.46L X 309 / 258X 468=

    V2 = 3.05L
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