What volume of 0.45 M LiOH would be needed to neutralize 60.0 mL of 0.15 M Hi?

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Marlene

Chemistry

8 June, 21:50

What volume of 0.45 M LiOH would be needed to neutralize 60.0 mL of 0.15 M Hi?

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Answers (1)

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Aracely Hahn · Answer 1

Answer is: volume of 0.45 M LiOH is 20 mL.

Chemical reaction: LiOH + HI → LiI + H₂O.

From chemical reaction: n (LiOH) : n (HI) = 1 : 1.

c (LiOH) · V (LiOH) = c (HI) · V (HI).

0.45 M · V (LiOH) = 0.15 M · 60.0 mL.

V (LiOH) = 0.15 M · 60.0 mL / 0.45 M.

V (LiOH) = 20 mL : 1000 mL/L = 0.02 L.

n - amount of the substance.

c - concentration of solution.