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19 June, 13:17

What is the ratio of [a-]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h-cooh) is 3.75?

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  1. 19 June, 13:38
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    The formula for pH given the pKa and the concentrations are:

    pH = pKa + log [a-]/[ha]

    Therefore calculating:

    3.75 = 3.75 + log [a-]/[ha]

    log [a-]/[ha] = 0

    [a-]/[ha] = 10^0

    [a-]/[ha] = 1
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