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Noelle Brown
Chemistry
28 December, 19:22
How many atoms are in 437g of silver
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Bentley Conrad
28 December, 19:36
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Answer: 2.44 x10²⁴ atoms Ag
Explanation: solution:
Convert mass of Ag to moles then convert moles to atoms of Ag using Avogadro's number.
437 g Ag x 1 mole Ag / 108 g Ag x 6.022x10²³ atoms Ag / 1 mole Ag
= 2.44x10²⁴ atoms Ag
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Bj
28 December, 19:49
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The answer to the question is 6.023
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