Ask Question
28 November, 00:59

Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fluid flow. A gasoline pump is measured to consume 3.5kW ofmechanical shaftpower when operating. The diameters of the outlet and inlet of the pump are the same and the pressuredifferential between them is 7 kPa. Determine the maximum possible volumeflow rateof gas

+5
Answers (1)
  1. 28 November, 01:04
    0
    maximum possible volume flow rate = V = 0.5m^3/s

    Explanation:

    Given power consumed = 3.5kW

    pressure difference (delta - P) = 7kPa

    let maximum possible volume flow rate = V

    The rate of flow of work = W = V x Delta - P

    hence, V = W/delta P

    V = 3.5/7

    V = 0.5m^3/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fluid flow. A ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers