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17 May, 09:32

What volume of a concentrated hcl solution, which is 36.0% hcl by mass and has a density of 1.179 g/ml, should be used to make 4.90 l of an hcl solution with a ph of 1.80?

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  1. 17 May, 10:00
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    (a) Calculate the molar concentration of the dil. HCl

    [H+] = 10^ (-pH) mol/L = 10^ (-1.80) mol/L = 0.015 85 mol/L

    (b) Calculate the mass of HCl in the dil. HCl

    Moles of HCl = 4.90 L dil solution * (0.015 85 mol HCl/1 L dil solution)

    = 0.077 66 mol HCl

    MM of HCl = (1.008 + 35.45) g/mol = 36.458 g/mol

    Mass of HCl = 0.077 66 mol HCl x (36.458 g HCl/1 mol HCl) = 2.831 g HCl

    (c) Calculate the volume of conc. HCl

    Mass of conc solution = 2.831 g HCl x (100 g conc solution/36.0 g HCl)

    = 7.865 g conc solution

    Volume of conc HCl

    = 7.865 g conc solution * (1 mL conc HCl/1.179 g conc solution)

    = 6.67 mL conc HCl
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