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Today, 16:25

What is the oxidation state of an individual sulfur atom in so42-?

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  1. Today, 16:38
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    The oxidation state of single oxygen atom is - 2 since it is more electronegative and like to gain electrons.

    The sum of the oxidation states of each atom = charge of compound

    Let’s say the oxidation state of Sulfur is x.

    Hence,

    x + 4 * (-2) = - 2

    x - 8 = - 2

    x = + 6

    The oxidation state of individual Sulfur atom is + 6
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