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2 August, 03:48

If 64 grams of o2 gas occupy a volume of 56 liters at a temperature or 25°c, what is the pressure of the gas, in atmospheres (atm) ?

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  1. 2 August, 04:14
    0
    Using Ideal Gas Laws:

    PV = nRT

    Where,

    P is Pressure = Not given

    V is the Volume = 56L

    n is number of moles of gas = Not given

    R is the proportionality constant = 0.08206 L. atm/K. mol

    T is the temperature = 25 + 273.15 = 298 K

    Step 1:

    Calculate n,

    n = 2 x 15.999 = 31.998 g/mole

    n (oxygen) = 64/31.998

    = 2 moles of oxygen

    Step 2:

    Calculate Pressure,

    P = nRT/V

    Substitute the values,

    P = 2 x 0.08206 x 298/56

    P = 0.88 atm
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