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3 May, 04:04

An apprentice jeweler determines the density of a sample of pure gold to be 20.3 g/cm3. the accepted value is 19.3 g/cm3. what is the percent error of the jeweler's density measurement?

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  1. 3 May, 04:07
    0
    We are tasked to find the percent error of the jeweler's density measurement through the formula:

    %Error = Absolute Value (Experimental Value - Theoretical value) x 100% / Theoretical Value

    We are given by the problem,

    Experimental Value=20.3 g/cm3

    Theoretical Value = 19.3 g/cm3

    By Substituting the details,

    %Error = Absolute Value (20.3 g/cm3 - 19.3 g/cm3) x 100% / 19.3 g/cm3

    %Error=Absolute Value (1) / 19.3

    %Error = 100/19.3

    %Error = 5.18%

    Therefore, 5.18% is the percent error committed by the jeweler
  2. 3 May, 04:15
    0
    accepted value - experimental value / accepted value * 100 = percent error (19.3 g/cm3 - 20.3 g/cm3) / (19.3 g/cm3) * 100% = 5.18 g/cm3
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