If δh = - 70.0 kj and δs = - 0.300 kj/k, the reaction is spontaneous below a certain temperature. calculate that temperature.

Question

Tiana Cruz

Chemistry

13 September, 12:35

If δh = - 70.0 kj and δs = - 0.300 kj/k, the reaction is spontaneous below a certain temperature. calculate that temperature.

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Noe Miranda · Answer 1

The temperature for the reaction is calculated as follows

delta H / delta S

delta H=-70 Kj

delta S = - 0.300 kj/k

temperature is therefore = - 70kj/-0.300kj/k = 233.33 K