The heat of fusion of lead is 23.1 J/g. How much heat is absorbed as 85.0 g melt at

328°C?

Q = 1964 J

Explanation:

Data Given:

latent heat of fusion for Lead (Lf) = 23.1 J/g

amount of ice (mass) = 85.0 gram

heat required to melt lead (Q) = ?

Solution:

Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.

Formula Used

Q = mLf

Q = heat required to melt a substance

m = mass of the substance

Lf = latent heat of fusion

put values in above formula

Q = mLf

Q = 85 g x 23.1 J/g

Q = 1964 J