How many moles of ammonium nitrate are in 335 ml?

Data Given:

Molarity = 0.425 mol/L

Volume = 335 mL

Moles = ?

Solution:

First of all convert volume from mL into L.

V = 335 / 1000 = 0.335 L

Applying formula of Molarity,

Molarity = moles of solute / Volume of solution

Solving for moles,

Moles = Molarity * Volume

Putting values,

Moles = 0.425 molL⁻¹ ₓ 0.335 L

Moles = 0.142 moles

Results:

Hence, when 0.142 moles of Ammonium nitrate taken and is added with enough water to make a volume of 335 mL, the molarity of the resulting solution will be 0.425 mol/dm³.