If the heat of fusion of water is 3.4 * 102 j/g, the amount of heat energy required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is

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Pongo

Chemistry

9 January, 09:17

If the heat of fusion of water is 3.4 * 102 j/g, the amount of heat energy required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is

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Logan Cervantes · Answer 1

If the heat of fusion of water is 3.4 * 10^2 joule/gram, the heat energy amount required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is 5100 joule (5100 = 3.4 x 10^2 x 15).

The problem above can be solved by using the heat of fusion formula. The formula for calculating the heat of fusion described as C = q/m, where: C is the heat of fusion, q is the amount of heat energy required, and m is the mass of the object.