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12 August, 08:29

What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?

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  1. 12 August, 08:33
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    Using the ideal gas law: PV=nRT

    P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

    (4.68) * (4.95) = (16.45) * (0.0821) * T

    Solve for T.

    T=17.15
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