If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

Question

Andrea Hayden

Chemistry

2 September, 02:31

If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

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Answers (1)

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Maeve Galvan · Answer 1

Answer is: 116,1 g of Li₃N.

Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.

m (LiOH) = 240g.

n (LiOH) = m (LiOH) : M (LiOH).

n (LiOH) = 240 g : 24 g/mol = 10 mol.

from chemical reaction: n (LiOH) : n (Li₃N) = 3 : 1.

10 mol : n (Li₃N) = 3 : 1.

n (Li₃N) = 3,33 mol.

m (Li₃N) = n (Li₃N) · M (Li₃N)

m (Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.