Calculate the ph of a solution in which [oh-]=7.1*10-3m. express the ph of the solution to two decimal places.

Answer is: pH value of solution is 11.85.

[ OH⁻] = 7.1·10⁻³ M; equilibrium concentration of hydroxide anions.

[OH⁻]·[H⁺] = Kw.

0.0071 mol/L · [H⁺] = 10⁻¹⁴ mol²/L².

[H⁺] = 10⁻¹⁴ mol²/L² : 7.1·10⁻³ mol/L.

[H⁺] = 1.4·10⁻¹² mol/L.

pH = - log[H⁺].

pH = - log (1.4·10⁻¹² mol/L).

pH = 11.85.

If pH is less than seven, solution is acidic; greater than seven, solution is basic; equal seven, solution is neutral.