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18 December, 18:27

Calculate the percentage of water in the hydrate manganese (ii) nitrate tetrahydrate

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Answers (2)
  1. 18 December, 18:35
    0
    Divide the mass of the water lost by the mass of hydrate and multiply by 100.

    Explanation:

    i think
  2. 18 December, 18:56
    0
    28.7%

    Explanation:

    First let us write the formula of manganese (ii) nitrate tetrahydrate. This is shown below:

    Mn (NO3) 2.4H2O

    The molar mass of Mn (NO3) 2.4H2O = 55 + 2[14 + (3x16) ] + 4[ (2x1) + 16]

    = 55 + 2[14 + 48] + 4[2 + 16]

    = 55 + 2[62] + 4[18]

    = 55 + 124 + 72

    = 251g/mol

    Mass of water of crystallization in Mn (NO3) 2.4H2O = 4H2O

    = 4[ (2x1) + 16]

    = 4[2 + 16]

    = 4[18]

    = 72g

    The percentage by mass of water of crystallization in manganese (ii) nitrate tetrahydrate Mn (NO3) 2.4H2O, is given by:

    Percentage of water of crystallization = Mass of water of crystallization / Molar Mass of Mn (NO3) 2.4H2O x 100

    = 72/251 x 100

    = 28.7%

    Therefore the percentage of water of crystallization in manganese (ii) nitrate tetrahydrate is 28.7%
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