At what temperature will 2.5 mol nitrogen gas exert a pressure of 10.0 atm in a 2.0-L container?

The answer to your question is T = 97.6 °K

Explanation:

Data

Temperature = T = ?

number of moles = n = 2.5

Pressure = P = 10 atm

Volume = V = 2 l

Constant of ideal gases = 0.082 atm l / mol°K

Process

1. - Write the formula of the ideal gas law

PV = nRT

-Solve for T

T = PV / nR

2. - Substitution

T = (10 x 2) / (2.5 x 0.082)

3. - Simplification

T = 20 / 0.205

4. - Result

T = 97.6 °K