N2 (g) + 3H2 (g) - > 2NH 3 (g)

Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.

a.) 17.04 g

b.) 84.4 g

c.) 56.2 g

d.) 85.2 g

Question

Rodrigo

Chemistry

11 January, 22:58

N2 (g) + 3H2 (g) - > 2NH 3 (g)

Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.

a.) 17.04 g

b.) 84.4 g

c.) 56.2 g

d.) 85.2 g

+2

Answers (1)

Know the Answer?

Joyce Reilly · Answer 1

None of the options are correct. The correct answer is:

56.67g

Explanation:

N2 + 3H2 - > 2NH3

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the equation,

6g of H2 produced 34g of NH3.

Therefore, 10g of H2 will produce = (10 x 34) / 6 = 56.67g of NH3

Therefore, 56.67g of NH3 are produced

N2 (g) + 3H2 (g) - > 2NH 3 (g)Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.a.) 17.04 gb.) 84.4 gc.) 56.2 gd.) 85.2 g

N2 (g) + 3H2 (g) - > 2NH 3 (g)

Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.

a.) 17.04 g

b.) 84.4 g

c.) 56.2 g

d.) 85.2 g