What volume of 0.500 M AgNO3 are needed to react with 100. mL of 0.400 M K2CrO4? 2 AgNO3 (aq) + K2CrO4 (aq) ➔ Ag2CrO4 (s) + 2 KNO3 (aq)

160 mL AgNO3 0.5 M

Explanation:

M = mol solute/L solution

mol solute = M * L solution

mol solute = (0.400 M * 0.1L) = 0.04 mol K2CrO4

2 mol AgNO3 - > 1 mol K2CrO4

x - > 0.04 mol K2CrO4 x = 0.08 mol AgNO3

L solution = mol solute/M

L solution = 0.08 mol AgNO3/0.500 M = 0.16 L = 160 mL