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30 January, 05:40

if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxygen?

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  1. 30 January, 05:46
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    Answer: 18.65L

    Explanation:

    Given that,

    Original volume of oxygen (V1) = 30.0L

    Original temperature of oxygen (T1) = 200°C

    [Convert temperature in Celsius to Kelvin by adding 273.

    So, (200°C + 273 = 473K) ]

    New volume of oxygen V2 = ?

    New temperature of oxygen T2 = 1°C

    (1°C + 273 = 274K)

    Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

    V1/T1 = V2/T2

    30.0L/473K = V2/294K

    To get the value of V2, cross multiply

    30.0L x 294K = 473K x V2

    8820L•K = 473K•V2

    Divide both sides by 473K

    8820L•K / 473K = 473K•V2/473K

    18.65L = V2

    Thus, the new volume of oxygen is 18.65 liters.
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