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7 January, 18:29

Given that diatomic chlorine is the most stable form of the element, and that the ΔHf° value for atomic chlorine is + 121.7 kJ/mol, calculate the maximum wavelength that can dissociate diatomic chlorine into monoatomic chlorine. What type of radiation (UV-A, UV-B, UV-C) does this wavelength correspond to?

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  1. 7 January, 18:35
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    The maximum wavelength of light that can dissociate diatomic chlorine into the monatomic chlorine form is 984 nm.

    Explanation:

    Given: ΔHf° value for atomic chlorine is + 121.7 kJ/mol

    1 Step

    Converting kJ/mol into kJ (knowing that in 1 mol there is 6.023*10^23 molecules)

    ΔHf° in kJ = 121.7 kJ/mol * 1 mole / 6.023*10^23

    ΔHf° = 2.02*10^-22 kJ

    ΔHf° = E = 2.02*10^-19 J

    2 Step

    Converting ΔHf° to a wavelength:

    knowing the E = h*C/У

    h = 6.626 x 10^-34 J·s

    C = 3.00 x 10^8 m/s

    У = h*C/E = (6.63 x 10^-34 J·s) (3.00 x 108 m/s) / 2.02*10^-19 J

    У = 9.84*10^-7 m = 984 nm

    3 Step (What type of radiation?)

    UV-A wavelength range = 315 nm to 400 nm

    UV-B wavelength range = 280 nm to 315 nm

    UV-C wavelength range = 100 nm to 280 nm

    This wavelength is not corresponding to any of the wavelength range (UV-A, UV-B, UV-C).
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