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19 April, 04:40

A volume of gas occupies 3.2 L at 2.8 kPa. What would the pressure be if the same volume of gas now occupied 8.1 L?

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  1. 19 April, 04:58
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    Answer: 1.09 kPa

    Explanation:

    Given that,

    Original volume V1 = 3.2 L

    Original pressure P1 = 2.8 kPa

    New pressure P2 = ?

    New volume V2 = 8.1 L

    Since pressure and volume are given While temperature is constant, apply Boyle's law

    P1V1 = P2V2

    2.8 kPa x 3.2L = P2 x 8.1L

    8.96 kPa L = P2 x 8.2L

    P2 = 8.96 kPa L / 8.2L

    P2 = 1.09 kPa

    Thus, the pressure of the gas would be 1.09 kPa
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