Measurements show that the enthalpy of a mixture of gaseous reactants increases by 130. kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that - 137. kJ of work is done on the mixture during the reaction.

Question

Hugo Crawford

Chemistry

14 June, 05:04

Measurements show that the enthalpy of a mixture of gaseous reactants increases by 130. kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that - 137. kJ of work is done on the mixture during the reaction.

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Jocelynn Ball · Answer 1

167 kJ

Explanation:

Given parameters

Change in enthalpy = 130 kJ (decrease)

Work done = - 137 kJ

Change in energy, / delta = ?

From the first law of thermodynamics:

ΔH = ΔE + PΔV,

Where, ΔH = change in enthalpy

ΔE = change in Internal energy

Substituting values into the above formula -

130 kJ = ΔE + - 137 kJ

130 kJ = ΔE - 137 kJ

therefore,

ΔE = (130 + 137) kJ

ΔE = 167 kJ

Therefore, the change in energy of the gas mixture during the reaction is 167 kJ.

Since the value of energy change Is positive, therefore this Is endothermic reaction