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13 August, 01:24

In the reaction C6H12 + __O2 → 6H2O + 6CO2, what coefficient should be placed in front of O2 to balance the reaction? 6 9 18 no coefficient is needed

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  1. 13 August, 01:36
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    The correct option is 9

    Explanation:

    The easiest way to balance any combustion equation is to first write the general form. In a combustion reaction the products are always carbon dioxide (CO2) and water (H2O) and the reactants are the organic material plus oxygen (O2).

    General Form:

    C6H12 + O2 - -> CO2 + H2O

    Now start by balancing the carbon atoms:

    six carbons on the left so you need 6 on the right.

    C6H12 + O2 - --> 6 CO2 + H2O

    Next balance the hydrogen atoms:

    12 on the left, so you need 12 on the right.

    C6H12 + O2 - -> 6CO2 + 6H2O

    Now count the number of oxygen on the right = 12 + 6 = 18

    Divide the number on the right by 2 to get the number needed on the left. 18/2 = 9
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