The atmosphere contained approximately 115 ppmv of anthropogenic co2 (g) in 2010. if 1 ppmv - co2 (g) is equivalent to 2184.82 tg-c (teragrams, or 1012 g, of atomic carbon), calculate how many metric tonnes of quicklime [cao (s) ] were needed to fix

Answer is: 3,2 · 10¹¹ t of quicklime.

Chemical reaction: CO₂ + CaO → CaCO₃.

m (CO₂) = 2184,82·10¹² · 115 = 2,51 · 10¹⁷ g.

n (CO₂) = m (CO₂) : M (CO₂)

n (CO₂) = 2,51 · 10¹⁷ g : 44 g/mol = 5,7 · 10¹⁵ mol.

from reaction n (CO₂) : n (CaO) = 1 : 1.

n (CaO) = 5,7· 10¹⁵ mol.

m (CaO) = 5,7· 10¹⁵ mol · 56 g/mol = 3,2 · 10¹⁷ g = 3,2 · 10¹¹ t.

n - amount of substance.