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4 March, 14:32

How many moles of o atoms are there in 25.0 g of hno3?

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  1. 4 March, 14:38
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    HNO3 molar mass = 1 + 14 + 3*16 = 63 g/mol

    # of moles = mass / molar mass - 25.0 g / 63 g = 0.3968 moles

    # of atoms = # of moles * Avogadro number = 0.3968 mol * 6.022 * 10^23 atoms/mol = 2.39 * 10^23 atoms
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