Determine the ph of a 0.227 m c5h5n solution at 25°c. the kb of c5h5n is 1.7 * 10-9.

the concentration of OH - using the formula:

[OH-] = Kw / [H+]

[OH-] = 1.0 x 10^-14 / ([ (1.7 x 10^-9) (0.227) ]^2)

[OH-] = 5.1 x 10^-10

To find the pOH, use the formula:

pOH = - log [OH-]

pOH = - log [5.1 x 10^-10]

pOH = 9.29