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28 January, 08:51

What volume of 0.812 m ammonium sulfate contains 7.65 g of ammonium ion?

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  1. 28 January, 09:13
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    The ammonium ion is NH4 + which should have a molecular weight of 18g/mol. Then, the amount of ammonium ion in mol should be 7.65g / (18g/mol) = 0.425 mol.

    The formula for ammonium sulfate would be (NH4) 2SO4. For every ammonium sulfate, you need 2 ammonium ion. Then the amount of ammonium sulfate in mol should be: 0.425 mol * (1/2) = 0.2125mol

    The volume of the solution would be: 0.2125mol / (0.812 mol/liter) = 0.26169l = 261.70 ml
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