What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass = 26 grams/mole) ?

(1) 1.3 M (3) 3.0 M

(2) 2.0 M (4) 0.75 M

Question

Emma Wilkerson

Chemistry

11 January, 08:40

What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass = 26 grams/mole) ?

(1) 1.3 M (3) 3.0 M

(2) 2.0 M (4) 0.75 M

+5

Answers (1)

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Conor Levine · Answer 1

The answer is (1) 1.3 M. The first thing you need to do is to convert the unit of gram to mole. The mol number of LiF is 52/26=2 mol. Then using the volume to calculate the molarity: molarity=2/1.5=1.3 M.

What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass = 26 grams/mole) ?(1) 1.3 M (3) 3.0 M(2) 2.0 M (4) 0.75 M

What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass = 26 grams/mole) ?

(1) 1.3 M (3) 3.0 M

(2) 2.0 M (4) 0.75 M