The average rate of consumption of br - is 1.86*10-4 m/s over the first two minutes. what is the average rate of formation of br2 during the same time interval?

By considering the reaction equation is:

5Br (aq) + BrO3 (aq) + 6H (aq) = 3Br2 (aq) + 3H2O (l)

when the average rate of consumption of Br = 1.86x10^-4 m/s

So from the reaction equation

5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So,

∴ 1.86x10^-4/5 = X / 3

∴X = 1.1 x 10^-4 m/s

∴the average rate of formation of Br2 = 1.1x10^-4 m/s