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8 December, 21:46

If the reaction produced 15.5 g CO2, how many grams of heptane were burned?

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  1. 8 December, 21:50
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    5 g of heptane were burned.

    Explanation:

    Given dа ta:

    Mass of CO₂ produced = 15.5 g

    Mass of heptane burned = ?

    Solution:

    Balance chemical equation:

    C₇H₁₆ + 11O₂ →7CO₂ + 8H₂O

    First of all we will calculate the moles of CO₂ produced.

    Number of moles = mass / molar mass

    Molar of CO₂ = 44 g/mol

    Number of moles = 15.5 g / 44 g/mol

    Number of moles = 0.3523 mol

    Now we will compare the moles of CO₂ and C₇H₁₆ from balance chemical equation

    CO₂ : C₇H₁₆

    7 : 1

    0.3523 : 1/7 * 0.3523 = 0.05 mol

    Mass of C₇H₁₆:

    Number of moles = mass / molar mass

    Mass = number of moles * molar mass

    Mass = 0.05 mol / 100 g/mol

    Mass = 5 g
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