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30 October, 18:04

Given that ∆G for the reaction below is - 957.9kj, what is ∆Gf of

H2O?

4NH3 (g) + 4NO (g) + 6H2O (g)

∆Gf, NH3=-16.66kj/mol

∆Gf, NO=86.71kj/mol

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  1. 30 October, 18:28
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    - 228.6 kJ/mol.

    Explanation:

    I got bandz
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