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5 April, 16:22

to prepare 100 mL of a 0.5 M solution of CuSO4 using water as the solvent. Calculate the amount of solid needed.

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  1. 5 April, 16:43
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    100 mL of a. 5 M solution

    = 0.1 L of. 5 M solution

    This solution will contain. 1 x. 5 mole of solute

    =.05 mole of solute

    molecular weight of CuSO₄

    = 63.5 + 32 + 64

    = 159.5 gm

    one mole of CuSO₄ = 159.5 gm

    .05 mole = 159.5 x. 05 gm

    = 7.975 gm

    7.975 gm of CuSO₄ will be required.
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