Calcium chloride is used to melt ice and snow on roads and sidewalks and to remove water from organic liquids. Calculate the molarity of a solution prepared by diluting 165 ml of 0.688 m calcium chloride to 925.0 ml.

Answer is: molarity of calcium chloride is 0.123 M.

V₁ (CaCl₂) = 165 mL; initial volume of calcium chloride solution.

c₁ (CaCl₂) = 0.688 M; initial concentration.

V₂ (CaCl₂) = 925.0 mL; final volume.

c₂ (CaCl₂) = ?; final concentration.

Use c₁V₁ = c₂V₂.

0.688 M · 165 mL = c₂ (CaCl₂) · 925 mL.

c₂ (CaCl₂) = (0.688 M · 165 mL) : 925 mL.

c₂ (CaCl₂) = 0.123 M.