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8 November, 13:29

Arrange the following bonds in order of increasing polarity: O-H, C-H, F-H, H-H

A) O-H

B) C-H<0-H

C) H-H

D) C-H

E) HH

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Answers (2)
  1. 8 November, 13:36
    0
    H-H < C-H < O-H < F-H

    Explanation:

    The polarity of a bond is the difference in the electronegativity of the elements. This property is the tendency of the atom to gain an electron and form an anion, or when in covalent bond (sharing electrons), to have the electron close to it.

    As higher is the atomic radius, as difficult it is to the atom to gain an electron because the attractive force will be less effective. So, the electronegativity increases from the bottom to top, and from the left to right in the periodic table.

    So, when the bond is between the same element, the polarity is 0, such as H-H. H has a low electronegativity, then it comes C, O, and F, so, the order of increasing of polarity is:

    H-H < C-H < O-H < F-H
  2. 8 November, 13:37
    0
    H-H < C-H < O-H < F-H
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