Determine the value of the equilibrium constant, Kgoal, for the reaction N2 (g) + H2O (g) ⇌NO (g) + 12N2H4 (g), Kgoal=? by making use of the following information: 1. N2 (g) + O2 (g) ⇌2NO (g), K1 = 4.10*10-31 2. N2 (g) + 2H2 (g) ⇌N2H4 (g), K2 = 7.40*10-26 3. 2H2O (g) ⇌2H2 (g) + O2 (g), K3 = 1.06*10-10 Express your answer numerically.

K = 1.79x10⁻³³

Explanation:

Using Hess's law, it is possible to fin K of a reaction by the algebraic sum of another related reactions.

In the reactions:

1. N2 (g) + O2 (g) ⇌ 2NO (g), K1 = 4.10*10-31 2.

2. N2 (g) + 2H2 (g) ⇌ N2H4 (g), K2 = 7.40*10-26

3. 2H2O (g) ⇌2H2 (g) + O2 (g), K3 = 1.06*10-10

The sum of 1/2 (1) + 1/2 (2) produce:

N2 (g) + 1/2O2 (g) + H2 (g) ⇌ 1/2N2H4 (g) + NO (g)

And K' = √4.1x10⁻³¹*√7.4x10⁻²⁶ = 1.74x10⁻²⁸

Now, this reaction + 1/2 (3):

N2 (g) + H2O (g) ⇌ NO (g) + 1/2N2H4 (g)

And K of reaction is:

1.74x10⁻²⁸*√1.06x10⁻¹⁰ = 1.79x10⁻³³