Instructions:Select the correct answer. If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is the limiting reagent? 2KNO3 + 10K 6K2O + N2

Question

Averi

Chemistry

25 June, 05:52

Instructions:Select the correct answer. If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is the limiting reagent? 2KNO3 + 10K 6K2O + N2

+3

Answers (2)

Know the Answer?

Charity Lopez · Answer 1

2KNO₃ + 10K = 6K₂O + N₂

n (K) = m (K) / M (K)

n (K) = 155g/39.1g/mol=3.964 mol

n (KNO₃) = m (KNO₃) / M (KNO₃)

n (KNO₃) = 122g/101.1g/mol=1.207 mol

K:KNO₃ = 10:2 = 5:1

3.964:1.207=3.3:1

K is the limiting reagent

Babykins · Answer 2

31310 / 390 = > 80.28 g of KNO3 (K is limiting reagent)