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1 July, 02:08

If you wish to warm 52 kg of water by 22 ∘c for your bath, find what the quantity of heat is needed. express your answer in calories cal.

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  1. 1 July, 02:35
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    Given:

    m = 52 kg. the mass of water

    ΔT = 22 °C, the temperature increase

    Note that

    c = 4.184 J / (g-°C), the specific heat of water.

    The quantity of heat required is

    Q = mcΔT

    = (52,000 g) * (4.184 J / (g-°C)) * (22 °C)

    = 4.7865 x 10⁴ J

    Because 1 J = 2.39 x 10⁻⁴ cal. the heat required is

    Q = (4.7865 x 10⁴ J) * (2.39 x 10⁻⁴ cal/J) = 1143.97 cal ≈ 1144 cal

    Answer: 1144 cal
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