Identify the pair of substances that would be soluble and form a solution when mixed. H2O solvent and I2 solute. H2O solvent and CCl4 solute H2O solvent and HCl solute CCl4 solvent and NaCl solute

H2O solvent and HCl solute.

Explanation:

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In this case, one can identify that neither iodine not carbon tetrachloride will be soluble in water since they are highly nonpolar unlike water. In addition, sodium chloride will not be soluble in carbon tetrachloride as they are ionic and nonpolar respectively, due to the lack of suitable intermolecular forces gathering them. Therefore water as solvent and hydrochloric as solute will form a solution when mixed as both of them are polar, nonetheless, the solubility of hydrochloric acid is about 37 grams of it per 100 g of water which means that no more than 37 grams are going the completely dissolve into maximum 100 g of water.

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Answer:H2O solvent and 12 solutes, H2O solvent CCl4