To begin the experiment, 1.11g of methane is burned in a bomb container containing 1000grams of water. The initial temperature is 24.85 C. The specific heat of water is 4.184 j/g C. The heat capacity is 698 J / C. The final water temperature is 35.65 C

Calculate the change in temperature

Formula for heat change: Q = mCΔTwhere

Q = the heat addedm = massC = specific heatΔT = (Tf - To in absolute temperature)

note: in this case subtracting the final and initial temperature in Kelvin or Celsius will not make a difference)

We add everything into the formula: ΔT = T (final) - T (original)

ΔT = 36.65 - 24.85ΔT = 11.8° CSo the change in temperature is 11.8 degrees

Q = 41.11x 4.319 x 11.8

Q=2095.13 heat of combustion of Methane.

It shows that burning 41.11g of methane gives of 2095.13 Joules of energy

The formula of heat added is presented as

Q = m * c * change in (T)

where

Q - the heat added

m - mass

c - specific heat

Change in temperature - (Tf - To)

Basically, in order for us to know the change in heat, the formula is

Change in temperature = T (final) - T (original)

Change in temperature = 36.65 - 24.85

Change in temperature = 11.8 degrees Celcius

So the change in temperature is 11.8 degrees