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10 August, 20:01

Calculate the poH of a substance with [OH-] of 3.0 x 10^-6 M.

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  1. 10 August, 20:10
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    Hello how are you doing
  2. 10 August, 20:12
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    pOH = 5.52

    Explanation:

    pOH = - log[OH] = - log[3.0 x 10^-6]

    pOH = 5.52
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