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13 August, 19:30

How many moles of mgbr2 are there in 118.0 g of that compound?

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  1. 13 August, 19:35
    0
    N=m/M

    M=24+80=104 g/mol

    m=118 g

    n=1.13 mol
  2. 13 August, 19:56
    0
    That would be 0.64 moles of MgBr2 in 118.0 grams.
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