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9 July, 00:30

A mixture of 0.600 mol bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C. Br2 (g) + I2 (g) 2 IBr (g). When the mixture has come to equilibrium, the concentration of iodine monobromide is 1.190 M. What is the equilibrium constant for this reaction at 350°C?

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  1. 9 July, 00:40
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    The answer to your question is Ke = 1.4751

    Explanation:

    Data

    bromine = 0.6 mol

    iodine = 1.6 mol

    volume = 1 L

    Ke = ?

    Iodine monobromide concentration = 1.190 M

    Process

    1. - Write the balanced chemical equation

    Br₂ + I₂ ⇒ 2IBr

    2. - Write the formula for Ke

    Ke = [IBr]²/[Br₂][I₂]

    3. - Substitution

    Ke = [1.19]² / [0.6][1.6]

    4. - Simplification

    Ke = 1.4161 / 0.96

    5. - Result

    Ke = 1.4751
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