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30 October, 22:04

Calculate the concentration of so42 - ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal places and include the appropriate units.

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  1. 30 October, 22:30
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    Answer: 0.00649M

    The question is incomplete,

    You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012

    With that you can solve the question following these steps"

    1) First ionization:

    H₂SO₄ (aq) - - > H⁺ (aq) + HSO₄⁻ (aq)

    Under the fully ionization assumption the concentration of HSO4 - is the same of the acid = 0.01 M

    2) Second ionization

    HSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012

    Do the mass balance:

    HSO₄⁻ (aq) H⁺ SO₄²⁻

    0.01 M - x x x

    Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]

    => Ka₂ = (x²) / (0.01 - x) = 0.012

    3) Solve the equation:

    x² = 0.012 (0.01 - x) = 0.00012 - 0.012x

    x² + 0.012x - 0.0012 = 0

    Using the quadratic formula: x = 0.00649

    So, the requested concentratioN is [SO₄²⁻] = 0.00649M
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