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27 September, 00:17

Find the [OH^-1] if the pH is 11.7

A) 1.0 x 10^-12 M

B) 2.9 x 10^-11 M

C) 1.5 x 10^-12 M

D) 2.0 x 10^12 M

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Answers (1)
  1. 27 September, 00:18
    0
    None of the options are correct.

    The answer to the question is 5.01x10^-3M

    Explanation:

    The following were obtained from the question:

    pH = 11.7

    Recall: pH + pOH = 14

    11.7 + pOH = 14

    pOH = 14 - 11.7

    pOH = 2.3

    Now we can obtain the [OH^-1] as follows:

    pOH = - Log [OH^-1]

    pOH = 2.3

    2.3 = - Log [OH^-1]

    -2.3 = Log [OH^-1]

    Take the anti-log of - 2.3

    [OH^-1] = 5.01x10^-3M
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