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18 December, 00:35

How many milliliters of 4.8 M NaOH are needed to exactly neutralize 29 milliliters of 2 M HCl?

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  1. 18 December, 00:47
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    V₁ = 12.1 mL

    Explanation:

    Given dа ta:

    Volume of NaOH required to neutralize = ?

    Molarity of NaOH = 4.8 M

    Volume of HCl = 20 mL

    Molarity of HCl = ?

    Solution:

    Chemical equation:

    HCl + NaOH → NaCl + H₂O

    In neutralization reaction the equal amount of H⁺ from acid and OH⁻ from base react to form water and salt is also formed.

    Formula:

    M₁V₁ = M₂V₂

    M₁ = molarity of NaOH

    V₁ = Volume of NaOH

    M₂ = molarity of HCl

    V₂ = volume of HCl

    Now we will put the values.

    4.8 M * V₁ = 2 M * 29 mL

    4.8 M * V₁ = 58 M. mL

    V₁ = 58 M. mL / 4.8 M

    V₁ = 12.1 mL
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