How many liters of H2O are produces @ STP by the combustion of 30g of CH4 CH4+2O2---> CO2 + 2H2O

Question

Cory Miranda

Chemistry

20 March, 21:15

How many liters of H2O are produces @ STP by the combustion of 30g of CH4 CH4+2O2---> CO2 + 2H2O

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Corinne Mcmillan · Answer 1

CH4+2O2---> CO2 + 2H2O

M (CH4) = 16.0 g/mol

30g CH4*1mol/16.0 g - mol of CH4

30g CH4 * (1mol/16.0 g) * (2 mol H2O/1 mol CH4) = 15 mol H2O

30g CH4 * (1mol/16.0 g) * (2 mol H2O/1 mol CH4) * 22.4L/1mol=84 L H2O as gas, but at STP water should be liquid, so

15 mol H2O*18g H2O/1 mol=270g of H2O

270g*1ml/1g = 270 ml = 0.27 L of liquid water, in reality it should be like this,

but I do not know what people who created this problem wanted H2O as liquid or as gas