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15 November, 10:51

Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside pressure of 2.4 atm.

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  1. 15 November, 11:15
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    The work done on the system is 17.75_KJ

    Explanation:

    To solve this question we need to know the required equations from the given variables, thus

    Initial volume = 85L

    Final volume = 12L

    External pressure = 2.4 atm.

    work done = - PΔV

    2.4 * (85-12) = 175.2L*atm

    Converting from L•atm to KJ is given by

    1 L•atm = 0.1013 kJ

    (175.2 L•atm) * (0.1013 kJ / 1 L•atm)

    = 17.75 kJ

    The work done on the system is 17.75_KJ
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