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5 January, 15:50

6K + B2O3 → 3K2O + 2B

How many moles of Boron can be produced if 3650g of B2O3 reacted?

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  1. 5 January, 15:55
    0
    104.84 moles

    Explanation:

    Given dа ta:

    Moles of Boron produced = ?

    Mass of B₂O₃ = 3650 g

    Solution:

    Chemical equation:

    6K + B₂O₃ → 3K₂O + 2B

    Number of moles of B₂O₃:

    Number of moles = mass / molar mass

    Number of moles = 3650 g / 69.63 g/mol

    Number of moles = 52.42 mol

    Now we will compare the moles of B₂O₃ with B from balance chemical equation:

    B₂O₃ : B

    1 : 2

    52.42 : 2*52.42 = 104.84

    Thus from 3650 g of B₂O₃ 104.84 moles of boron will produced.
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